Answer:
6 with multiplicity 2
-2 with multiplicity 2
Explanation:
We have given that find the roots of:
f (x) = (x- 6)²(x + 2)²
Note that the polynomials are already in the factored form. So we will only make it equal to zero
(x-6)² = 0
The square tells us that the root repeat twice
Move -6 to the R.H.S
Then,
x=6 , 6
(x+2)²=0
Move 2 to the R.H.S
Then,
x= -2, -2
Therefore the correct options are:
6 with multiplicity 2
-2 with multiplicity 2 ....