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Find the root(s) of f (x) = (x- 6)2(x + 2)2.

-6 with multiplicity 1

-6 with multiplicity 2

6 with multiplicity 1

6 with multiplicity 2

-2 with multiplicity 1

-2 with multiplicity 2

2 with multiplicity 1

2 with multiplicity 2

User Rafalmp
by
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2 Answers

5 votes

Answer:

4 and 6

Explanation:

User Shaun Neal
by
8.5k points
3 votes

Answer:

6 with multiplicity 2

-2 with multiplicity 2

Explanation:

We have given that find the roots of:

f (x) = (x- 6)²(x + 2)²

Note that the polynomials are already in the factored form. So we will only make it equal to zero

(x-6)² = 0

The square tells us that the root repeat twice

Move -6 to the R.H.S

Then,

x=6 , 6

(x+2)²=0

Move 2 to the R.H.S

Then,

x= -2, -2

Therefore the correct options are:

6 with multiplicity 2

-2 with multiplicity 2 ....

User Satyadeep
by
8.1k points

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