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2 votes
Identify the intercepts of the circle (x-5)^2+(y+12)^2=169

2 Answers

3 votes

Answer:

x-intercept: (10,0) , (0,0)

y-intercept: (0,0) , (0,-24)

User Tarun Tyagi
by
5.6k points
1 vote

Explanation:

The x-intercept is the point where the graph touches the x-axis, which means y=0. So let's set y=0 in your equation, and we receive

(x-5)^2 + (0+12)^ = 169

which means

(x-5)^2 = 25

Solve this, and get x=10 or x=0.

This means the x-intercepts are (10,0) and (0,0).

Try doing the same for y.

User Xavier Dury
by
5.5k points
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