Answer:
Option C is correct.
Explanation:
![\theta=(5\pi )/(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9iwg5boc43euhef4nnxzhzh19tyw2ejedq.png)
We need to find reference angle and signs of sinФ, cosФ and tanФ
We know that
is equal to 150°
and 150° is in 2nd quadrant.
So, Ф is in 2nd quadrant.
And In 2nd quadrant sine is positive, while cos and tan are negative
The reference angle Ф' is found by: π - Ф
=> Ф = 5π/6
so, Reference angle Ф' = π - 5π/6
Ф' = 6π - 5π/6
Ф' = π/6
So, Option C Θ' = pi over 6; sine is positive, cosine and tangent are negative is correct.