The slope intercept forth of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point slope form of the equation for this line?

Question

asked Jan 1, 2020 139k views

1 Answer

Steve McKay · Answer 1 · 2020-01-05T21:06:19+0000

Answer:

Explanation:

The point-slope form of an equation:

y-y_1=m(x-x_1)

m - slope

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

We have the equation of a line:

y=5x-3

therefore the slope m = 5.

Put the value of the slope and the coordinates of the given point (-2, -13) to the equation of a line:

$y-(-13)=5(x-(-2))\\\\y+13=5(x+2)$