Send it quick guys...

Question

asked Mar 8, 2020 963 views

1 Answer

Jake Thompson · Answer 1 · 2020-03-13T04:49:34+0000

Answer:

194

Explanation:

Recall 2 rules to solve this easily:

1.
(a+b)^2=a^2+2ab+b^2

2.
(a-b)^2=a^2-2ab+b^2

Now, if we let a = 7 and
, we can say the problem is basically of the form:

(a+b)^2 + (a-b)^2

This can be simplified using the rules:

$(a+b)^2 + (a-b)^2\\a^2+2ab+b^2+a^2-2ab+b^2\\2a^2+2b^2$

Now we can plug the values of a and b we initially thought of (remember though
√(x) √(x) =x ):

$2a^2+2b^2\\2(7)^2+2(4√(3))^2\\ 2(49)+2(4√(3))(4√(3))\\98+2(4)(4)(√(3) )(√(3) )\\98+2(4)(4)(3)\\98+96 \\194$

194 is the final answer.