Question

A classroom floor has an area of

(30x3 + 8x2) ft, with a width of 2x feet.
What is the length of the floor?

Answer 1

The length of the floor is
`(15x^(2)+4x)\ ft`

Explanation:

we know that

The area of a rectangle ( classroom floor) is equal to

`A=LW`

in this problem we have

`A=(30x^(3)+8x^(2))\ ft^(2)`

`W=2x\ ft`

substitute in the formula and solve for L

`(30x^(3)+8x^(2))=2x(L)`

Divide by 2x both sides

`L=(15x^(2)+4x)\ ft`