Question

Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.

sin(45°) = 

sin(45°) = 

9 tan(45°) = AC 

(AC)sin(45°) = BC

cos(45°) = ​

Answer 1

A

E

Explanation:

Answer 2

sin(45°)= AC/9

cos(45°)= BC/9

Explanation:

This is a right angle triangle:

∠ABC =∠CAB = 45°

Now

AC= CB

AB = 9 units.

We will apply sines:

sine(45°)= AC/AB

We know that AB = 9 units.

So substitute the value of side AB

sin(45°)= AC/9

Now apply cos(45°)

cos(45°)= BC/AB

Again substitute the value of AB:

cos(45°)= BC/9

Thus the answer is

sin(45°)= AC/9

cos(45°)= BC/9 ....