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Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow

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Answer:


\omega_y,\omega_x,\omega_Z all are zero.

Step-by-step explanation:

We know that if flow is possible then it will satisfy the below equation


(\partial u)/(\partial x)+(\partial v)/(\partial y)+(\partial w)/(\partial z)=0

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function
\phi given as follows


u=-(\partial \phi )/(\partial x),v=-(\partial \phi )/(\partial y),w=-(\partial \phi )/(\partial z)

Rotationality of fluid is given by
\omega


(\partial v)/(\partial x)-(\partial u)/(\partial y)=\omega_Z


(\partial v)/(\partial z)-(\partial w)/(\partial y)=\omega_x


(\partial w)/(\partial x)-(\partial u)/(\partial z)=\omega_y

So now putting value in the above equations ,we will find


\omega =(\partial \phi )/(\partial x),u=(\partial \phi )/(\partial x),


\omega_y=(\partial^2 \phi )/(\partial z\partial x)-(\partial^2 \phi )/(\partial z\partial x)

So
\omega_y=0

Like this all
\omega_y,\omega_x,\omega_Z all are zero.

That is why velocity potential flow is irroational flow.

User Maryam Homayouni
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