Question

Please help!!

If a mass on a spring is 9 kg and the spring constant is 1 N/m, what would be its period?
A. 3 s
B. π s
C. 6 πs
D. 3 πs

Answer 1

C. 6π s

Step-by-step explanation:

Time period of a mass-spring system

`\sf T=2 \pi \sqrt{(m)/(k)`

where:

• T = time period (s)
• m - mass (kg)
• k = spring constant (N m⁻¹)

Given:

• m = 9 kg
• k = 1 N m⁻¹

Substitute the given values into the formula:

`\implies \sf T=2 \pi \sqrt{(9)/(1)`

`\implies \sf T=2 \pi √(9)`

`\implies \sf T=2 \pi (3)`

`\implies \sf T=6 \pi \:\:s`

Answer 2

C. 6 πs

Answer:

Solution Given:

Mass of the string [m]=9kg

Spring constant [k]= 1N//m

Period [T]=?

weight of the body [F] =9*10=90 N

we have

Time period [T] =
`2\pi \sqrt{(m)/(k)}`=
`2\pi \sqrt{ *(9)/(1)}`=6
`\pi` second