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3 votes
Prove that if AB= 0and A is invertible then B= 0

User Max Markov
by
5.0k points

1 Answer

4 votes

Answer with Step-by-step explanation:

Since we have given that

AB = 0 and A is invertible so, AA⁻¹ = I

So, Consider,


AB=0

Multiplying A⁻¹ on both the sides, we get that


A^(-1)AB=A^(-1)0\\\\(AA^(-1))B=0\\\\IB=0\\\\B=0

Hence proved.

User Tom Goodfellow
by
6.2k points
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