Question

Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the earth's air-soil surface. The outside diameter of the container is 2.0 m, and 500 W of heat are released as a result of radloactive decay. If the soll surface temperature is 25*C, what is the outslde surface temperature of the contalner?

Answer 1

Outside temperature =88.03°C

Step-by-step explanation:

Conductivity of air-soil from standard table

K=0.60 W/m-k

To find temperature we need to balance energy

Heat generation=Heat dissipation

Now find the value

We know that for sphere

`q=(2\pi DK)/(1-(D)/(4H))(T_1-T_2)`

Given that q=500 W

so

`500=(2\pi 2* .6)/(1-(2)/(4* 10))(T_1-25)`

By solving that equation we get

`T_2`=88.03°C

So outside temperature =88.03°C