15.9k views
5 votes
graph and show points for 3x+6yless than or equal to 12, -x+y greater than or equal to 0, x is greater than or equal to 0, y is greater than or equal to 0. Please show points and shading? Im confused bad

1 Answer

2 votes

Answer:

Explanation:

Given equations are


3x+6y\leq 12


-x+y\geq 0

Now the inequalities intersect at x=
(4)/(3)

y=
(4)/(3)

and we have to satisfy this also


x\geq 0


y\geq 0

Above all conditions is shown in graph

and the shaded area is the required area

For
3x+6y\leq 12 put (0,0)

it satisfy the point i.e. (0,0) lie on that side which satisfy the inequality similarly check for


-x+y\geq 0

put (4,0) it do not satisfy the inequality therefore it lies on the side which do not satisfy the inequality

graph and show points for 3x+6yless than or equal to 12, -x+y greater than or equal-example-1
User Jerome Indefenzo
by
5.6k points