Question

Calculate the wire pressure for a round copper bar with an original cross-sectional area of 12.56 mm2 to a 30% reduction of area, given that the included die angle is 300 with a coefficient of friction (μ) of 0.08 and the yield stress for copper is 350 MPa.

Answer 1

Answer:153.76 MPa

Step-by-step explanation:

`Initial Area\left ( A_0\right )=12.56 mm^2`

`Final Area\left ( A_f\right )=0.7* 12.56 mm^2=8.792 mm^2`

`Die angle=30^(\circ)`

`\alpha =(30)/(2)=15^(\circ)`

`\mu =0.08`

`Yield stress\left ( \sigma _y \right )=350 MPa`

`B=\mu cot\left ( \aplha\right )=0.2985`

`\sigma _(pressure)=\sigma _y\left [(1+B)/(B)\right ]\left [ 1-(A_f)/(A_0)\right ]^B`

`\sigma _(pressure)=350\left [(1+0.2985)/(0.2985)\right ]\left [ 1-(8.792)/(12.56)\right ]^(0.2985)`

`\sigma _(pressure)=153.76 MPa`