Question

Iana started to evaluate the function f(x) = 2x2 – 3x + 7 for the input value 2.

f(x) = 2(2)2 – 3(2) + 7

= 2(4) – 3(2) + 7

What is the value of the function when x = 2?

Answer 1

`\large\boxed{\text{f}(2)=9}}`

Explanation:

In this question, we're solving for the function when x = 2

What this means is that you would plug the number 2 in every "x" value.

When you plug in the 2's, your equation should look like this:

`\text{f}(2)=2(2)^2-3(2)+7`

Now, you would solve to get your answer.

`\text{f}(2)=2(2)^2-3(2)+7\\\\\text{You would carry over the exponent to the number 2 in the parenthesis,}\\\text{That would be equivalent to 2 * 2, making it 4.}\\\\\text{f}(2)}=2(4)-3(2)+7\\\\\text{f}(2)}=8-3(2)+7\\\\\text{f}(2)}=8-6+7\\\\\text{f}(2)}=9`

When you're done solving, you should get 9.

This means that f(2) = 9

I hope this helped you out.

Good luck on your academics.

Have a fantastic day!

Answer 2

9

Explanation:

f(x)=2x^2-3x+7

To find the value of the function at f(2), you just replace x with 2:

f(2)=2(2)^2-3(2)+7

f(2)=2(4)-3(2)+7

This is as far as she got. She is doing great so far.

f(2)=8-6+7

f(2)=2+7

f(2)=9

The value of the function at x=2 is 9.