Calculate the value of D at 705°C for the diffusion of some species in a metal for which the values of D0 and Qd are 4.5 × 10-5 m2/s and 164 kJ/mol, respectively.

Question

asked Jul 28, 2020 131k views

1 Answer

Jerode · Answer 1 · 2020-08-02T23:29:07+0000

Answer:

The value of D is
$7.753*10^(-14)\ m^2/s$

Step-by-step explanation:

Given that,

Temperature = 705°C

Maximum diffusion
$D_(0)=4.5*10^(-5)\ m^2/s$

Activation energy
Q_(d) = 164 kJ/mol

We need to calculate the value of D

Using formula of diffusion coefficient

$D=D_(0)\ exp\ ((-Q_(d))/(RT))$

Where, D = diffusion coefficient

D_(0) = Maximum diffusion coefficient

Q_(d) = Activation energy

T = temperature

R = Gas constant

Put the value into the formula

$D=4.5*10^(-5)\ exp\ ((-164*10^(3))/(8.31*705+273))$

$D=7.753*10^(-14)\ m^2/s$

Hence, The value of D is
$7.753*10^(-14)\ m^2/s$