Question

A circular rod with a gage length of 4 m and a diameter of 2.3 cm is subjected to an axial load of 70 kN . If the modulus of elasticity is 200 GPa , what is the change in length?

Answer 1

The change in length is 3.4 mm.

Step-by-step explanation:

Given that,

Length = 4 m

Diameter = 2.3 cm

Load = 70 kN

Modulus of elasticity = 200 GPa

We need to calculate the change in length

Using formula of modulus of elasticity

`E=((F)/(A))/((\Delta l)/(l))`

`\Delta l=(Fl)/(AE)`

Where, F = force

A = area

L = length

E = modulus elasticity

Put the value into the formula

`\Delta l=(70*10^(3)*4)/(\pi*(1.15*10^(-2))^2*200*10^(9))`

`\Delta l=0.00336\ m`

`\Delta l=3.4\ mm`

Hence, The change in length is 3.4 mm.