Question

When adjusted for any changes in ΔH and ΔS with temperature, the standard free energy change ΔG∘T at 2400 K is equal to 1.22×105J/mol . Calculate the equilibrium constant at 2400 K .

Answer 1

K=0.0022

Step-by-step explanation:

ΔG° = 1.22×10⁵ J/mol

Temperature (T) = 2400 K

ΔG° = - RT ln K

where R is gas constant whose value is 8.314 J/Kmol

K is equilibrium constant

ΔG° standard free energy

ln K =
`-(\Delta G^o )/(RT)`

K =
`e^{-(\Delta G^o )/(RT)}`

K =
`e^{-(1.22 * 10^5 )/(8.314 * 2400)}`

K= 0.0022

hence equilibrium constant value is K=0.0022