Question

g A box having mass 0,5kg is placed in front of a 20 cm compressed spring. When the spring released, box having mass m1, collide box having mass m2 and they move together. Find the velocity of boxes.

Answer 1

Answer:Expression given below

Step-by-step explanation:

Given mass of spring
`\left ( m_1\right )=0.5 kg`

Compression in the spring
`\left ( x\right )=20 cm`

Let the spring constant be K

Using Energy conservation

potential energy stored in spring =Kinetic energy of Block
`\left ( m_1\right )`

`(1)/(2)Kx^2=(1)/(2)m_1v^2`

`v=x\sqrt{(k)/(m_1)}`

now conserving momentum

`m_1v=\left ( m_1+m_2\right )v_0`

`v_0=(m_1)/(m_1+m_2)v`

where
`v_0` is the final velocity