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Prove the following statement is true by providing an example.

There is an integer that is divisible by 6 and is also divisible by 8, but is not divisible by 48.

User Sergpank
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Answer:

The statement "There is an integer that is divisible by 6 and is also divisible by 8, but is not divisible by 48." is true.

Explanation:

Consider the provided information.

We need to prove that there exist an integer that is divisible by 6 and is also divisible by 8, but is not divisible by 48 with the help of an example.

The prime factors of the number 6 is:

6 = 2 × 3

The prime factors of the number 8 is:

8 = 2 × 2 × 2

Now the Least Common Multiple of the number 6 and 8 is:

2 × 2 × 2 × 3 = 24

Since, it is clear that the number 24 is divisible by 6 and 8 but the number is not divisible by 48.

There exist infinite numbers which can be divisible by 6 and 8 but not divisible by 48.

All the odd multiples of 24 are divisible by 6 and 8 but all the odd multiples of 24 are not divisible by 48.

For example:

24 × 3 = 72 (The number is divisible by 6 and 8 but not divisible by 48.)

24 × 5 = 120 (The number is divisible by 6 and 8 but not divisible by 48.)

Hence, the statement "There is an integer that is divisible by 6 and is also divisible by 8, but is not divisible by 48." is true.

User Ranjit Kumar
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