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A football is kicked vertically upward from a height of 22 feet with an initial speed of 7575 feet per second. The formula h equals 2 plus 75 t minus 16 t squaredh=2+75t−16t2 describes the​ ball's height above the​ ground, h, in​ feet, t seconds after it was kicked. Use this formula to find the​ ball's height 22 secondsseconds after it was kicked. The​ ball's height, 22 secondsseconds after it was​ kicked, was 3131 feet.

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Answer:

time, t = 22seconds

height from kick, h = 22 + 75t -16t^2...eq1

subst for t = 22 in eq1

=> h = 22 + 75(22) - 16(22^2)

=> h = 22 + 1650 - 7744 = -6072ft

since h is negative it means ball is on the ground

User Lee Hampton
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