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Charles has collected data to find that the total snowfall per year in Reamstown has a normal distribution. Using the Empirical Rule, what is the probability that in a randomly selected year, the snowfall was less than 87 inches if the mean is 72 inches and the standard deviation is 15 inches? Provide the final answer as a percent.

User Moodywoody
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2 Answers

3 votes

Answer:

Explanation:

Correct answers:

84%

Notice that 87 inches is one standard deviation greater than the mean. Based on the Empirical Rule, 68% of the yearly snowfalls are within one standard deviation of the mean. Since the normal distribution is symmetric, this implies that 16% of the yearly snowfalls are greater than one standard deviation above the mean. Alternatively, 84% of the yearly snowfalls are less than one standard deviation above the mean.

User Jesse Hallett
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6.2k points
5 votes

Answer:

0.8413 or 84.13%

Explanation:

Given : The mean is 72 inches and the standard deviation is 15 inches

To Find : What is the probability that in a randomly selected year, the snowfall was less than 87 inches

Solution:

Mean =
\mu = 72

Standard deviation =
\sigma = 15

Formula :
z=(x-\mu)/(\sigma)

We are supposed to find the probability that in a randomly selected year, the snowfall was less than 87 inches

So, x = 87

Substitute the values in the formula


z=(87-72)/(15)


z=1

Now to find P(z<87) refer the z table

P(Z<87)=0.8413 = 84.13%

So, the probability that in a randomly selected year, the snowfall was less than 87 inches if the mean is 72 inches and the standard deviation is 15 inches is 0.8413 or 84.13%

User AndySavage
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