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In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

1 Answer

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Answer:

x ≥ 9

Explanation:

we have


2x-7 \geq 11

solve for x

Adds 7 both sides


2x\geq 11+7


2x\geq 18

Divide by 2 both sides


x\geq 18/2


x\geq 9

The solution is the interval -----> [9,∞)

In set builder notation

x ≥ 9

All real numbers greater than or equal to 9

User Delian Krustev
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