In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

Question

asked Dec 11, 2020 48.4k views

1 Answer

Delian Krustev · Answer 1 · 2020-12-16T06:04:08+0000

Answer:

x ≥ 9

Explanation:

we have

$2x-7 \geq 11$

solve for x

Adds 7 both sides

$2x\geq 11+7$

$2x\geq 18$

Divide by 2 both sides

$x\geq 18/2$

$x\geq 9$

The solution is the interval -----> [9,∞)

In set builder notation

x ≥ 9

All real numbers greater than or equal to 9