Question

In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11?

Answer 1

x ≥ 9

Explanation:

we have

`2x-7 \geq 11`

solve for x

Adds 7 both sides

`2x\geq 11+7`

`2x\geq 18`

Divide by 2 both sides

`x\geq 18/2`

`x\geq 9`

The solution is the interval -----> [9,∞)

In set builder notation

x ≥ 9

All real numbers greater than or equal to 9