Answer:
The correct option is C
Explanation:
The given expression is:
=y²+7y+12/y²-3y-18
Break the middle term of both the numerator and denominator:
=y²+4y+3y+12/y²-6y+3y-18
Take the common from the expressions:
=y(y+4)+3(y+4)/y(y-6)+3(y-6)
=(y+3)(y+4)/(y+3)(y-6)
The same terms will be cancelled: Then we have,
=(y+4)/(y-6)
Therefore the correct option is C....