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Find the center and radius of the circle whose equation is x^2 + y^2 - 6x - 2y + 4 = 0

Find the center and radius of the circle whose equation is x^2 + y^2 - 6x - 2y + 4 = 0-example-1

2 Answers

7 votes

Answer: Answer Choice A

(3,1) square root 6

Explanation:

User AwokeKnowing
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4 votes

Answer:

center(3,1) radius square root of 6

Explanation:

(x^2-6x+9)+(y^2-2y+1)=6

(x-3)^2+(y-1)^2=6

User Bjorg P
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