Question

Find an equation for the line that passes through the points (-2, 1) and (6, -5)

Answer 1

y=-3/4x-1/2

Explanation:

Using the slope equation,

m=y₂-y₁

____

x₂-x₁

you get the slope:

m=-5-1/6+2

m=-6/8

m=-3/4

We find that the intercept is -1/2.

The equation is y=-3/4x-1/2

Answer 2

Hello!

The answer is:

The equation of the line that passes through the points (-2,1) and (6,-5) is:

`y=-(3)/(4)x-(1)/(2)`

Why?

To solve the problem, we can use the following formula:

We have that:

`y-y_1=(y_2-y_1)/(x_2-x_1)*(x-x_1)`

So, using the given points (-2,1) and (6,-5), we have:

`y-1=(-5-1)/(6-(-2))*(x-(-2))`

`y-1=(-6)/(6+2)*(x+2)`

`y-1=(-6)/(8)*(x+2)`

`y-1=-(3)/(4)*(x+2)`

`y=-(3)/(4)*(x+2)+1`

`y=-(3)/(4)*(x)-(3)/(4)**(2)+1`

`y=-(3)/(4)(x)-(6)/(4))+1`

`y=-(3)/(4)(x)-(3)/(2))+1`

`y=-(3)/(4)x-(1)/(2)`

Hence, we have that the equation of the line that passes through the points (-2,1) and (6,-5) is:

`y=-(3)/(4)x-(1)/(2)`

Have a nice day!