8.1k views
5 votes
Please help me. these problems


Please help me. these problems ​-example-1
User Dagelf
by
7.4k points

1 Answer

5 votes

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Explanation:

You are comparing to
\sum_(k=1)^(\infty) a_1(r)^(k-1)

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is
(a_1)/(1-r) where
a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:


(a_1)/(1-r)=(3)/(1-(1)/(2))=\frac{3}{(1)/(2)=6

The second series has r=1/6 and a_1=420 giving me:


(420)/(1-(1)/(6))=(420)/((5)/(6))=420((6)/(5))=504.

User Caoyufei
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories