Question

A motorboat is moving at 4.0 m/s when it begins to accelerate at 1.0 m/s2. To the nearest tenth of a second, how long does it take for the boat to reach a speed of 17.0 m/s?

Answer 1

13 sec

Step-by-step explanation:

Hello

by definition the acceleration is a vector derived magnitude that indicates the speed variation per unit of time

`a=(V_(f)-V_(i))/(t_(f)-t_(i))\\a(t_(f)-t_(i))={V_(f)-V_(i)  }}\\t_(f)-t_(i)=(V_(f)-V_(i))/(a) \\\\t_(f)=(V_(f)-V_(i))/(a)+t_(i) \\\\`

Let

Vi=4.0 m/s

a=1.0 m/s2

Vf=17.0 m/s

ti= (0)sec

t2= unknown

`t_(f)=(V_(f)-V_(i) )/(a)+t_(i)\\t_(f)=(17-4 )/(1)+0\\t_(f)=\ 13\ sec\\`

Answer: 13 sec

I hope it helps