Question

What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273K under 75kPa?

Answer 1

Step-by-step explanation:

Given parameters:

Number of moles = 12moles

Temperature = 273K

Pressure = 75kPa, convert to atm:

1kPa = 0.00986923atm

75kPa = 75 x 0.00986923 = 0.74atm

Unknown:

Volume of the oxygen gas

Solution:

We simply apply the idea gas law which is :

PV = nRT

Since the unknown is volume, we make it the subject of the formula:

V =
`(nRT)/(P)`

R is the gas constant and its value is given as 0.082

V =
`(12 x 0.082 x 273 )/(0.74)` = 363.01L