Answer:
23.4 m/s
Step-by-step explanation:
f = actual frequency of the wave = 6.2 x 10⁹ Hz
= frequency observed as the ball approach the radar
= frequency observed as the ball recede away from the radar
V = speed of light
= speed of ball
B = beat frequency = 969 Hz
frequency observed as the ball approach the radar is given as
eq-1
frequency observed as the ball recede the radar is given as
eq-2
Beat frequency is given as
![B = f_(app) - f_(rec)](https://img.qammunity.org/2020/formulas/physics/college/6gade3r89ouodud2j19k7vhg9uf7s482kj.png)
Using eq-2 and eq-1
![B = (f(V+v))/(V)- (f(V-v))/(V)](https://img.qammunity.org/2020/formulas/physics/college/fhn96mwcq23ohq50rqzb62772i3qa45n3e.png)
inserting the values
![969 = ((6.2* 10^(9))((3* 10^(8))+v))/((3* 10^(8)))- ((6.2* 10^(9))((3* 10^(8))-v))/((3* 10^(8)))](https://img.qammunity.org/2020/formulas/physics/college/y4fucb8b5iag6r94myq2r2rlnu3gbpgqz3.png)
= 23.4 m/s