Answer:
23.4 m/s
Step-by-step explanation:
f = actual frequency of the wave = 6.2 x 10⁹ Hz
= frequency observed as the ball approach the radar
= frequency observed as the ball recede away from the radar
V = speed of light
= speed of ball
B = beat frequency = 969 Hz
frequency observed as the ball approach the radar is given as
eq-1
frequency observed as the ball recede the radar is given as
eq-2
Beat frequency is given as

Using eq-2 and eq-1

inserting the values

= 23.4 m/s