Question

Tool life testing on a lathe under dry cutting conditions gauge 'n' and 'C' of Taylor tool life equation as 0.12 and 130 m/min. respectively. When a coolant was used, 'C' increased by 10%. The increased tool life with the use of coolant at a cutting speed of 90 m/min is

Answer 1

So % increment in tool life is equal to 4640 %.

Explanation:

Initially n=0.12 ,V=130 m/min

Finally C increased by 10% , V=90 m/min

Let's take the tool life initial condition is
`T_1` and when C is increased it become
`T_2`.

As we know that tool life equation for tool

`VT^n=C`

At initial condition
`130* (T_1)^(0.12)=C`------(1)

At final condition
`90* (T_2)^(0.12)=1.1C`-----(2)

From above equation

`(130* (T_1)^(0.12))/(90* (T_2)^(0.12))=(1)/(1.1)`

`T_2=47.4T_1`

So increment in tool life =
`(T_2-T_1)/(T_1)`

=
`(47.4T_1-T_1)/(T_1)`

So % increment in tool life is equal to 4640 %.