Question

The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump has 98% efficiency, what would have been the enthalpies at the inlet and outlet if the pump was 100% efficient?

Answer 1

Answer:500,551.02

Step-by-step explanation:

Given

Initial enthaly of pump \left ( h_1\right )=500KJ/kg

Final enthaly of pump \left ( h_2\right )=550KJ/kg

Final enthaly of pump when efficiency is 100%=
`h_2^(')`

Now pump efficiency is 98%

`\eta`=
`(h_2-h_1)/(h_2^(')-h_1)`

0.98=
`(550-500)/(h_2-500)`

`h_2=551.02KJ/kg`

therefore initial and final enthalpy of pump for 100 % efficiency

initial=500KJ/kg

Final=551.02KJ/kg