Answer:
The work done on the test charge is 4.5 joules
Step-by-step explanation:
It is given that,
Electric potential difference,

Charged particle,

Work done on the test charge is given by the product of test charge and potential difference i.e.
W = q × V

W = 4.5 Joules
So, the work done on the test charge is 4.5 joules. Hence, this is the required solution.