Answer:
The work done on the test charge is 4.5 joules
Step-by-step explanation:
It is given that,
Electric potential difference,
![V=1000\ V](https://img.qammunity.org/2020/formulas/physics/college/zgzrkd18igv3nv2gz9l9uxiamhvsb5nmlw.png)
Charged particle,
![q=4.5* 10^(-3)\ C](https://img.qammunity.org/2020/formulas/physics/college/mt4eh7x8xtpzw6wbpsrtpsjdf3tecbl8ig.png)
Work done on the test charge is given by the product of test charge and potential difference i.e.
W = q × V
![W=4.5* 10^(-3)\ C* 1000\ V](https://img.qammunity.org/2020/formulas/physics/college/xdeolbhd2k2kkk7y2p89pbaeyimmo6d9hh.png)
W = 4.5 Joules
So, the work done on the test charge is 4.5 joules. Hence, this is the required solution.