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Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.55 μC charge and flies due west at a speed of 685 m/s over the Earth's south magnetic pole, where the 8.00 x 10^-5 T magnetic field points straight up. What is the magnitude of the magnetic force on the plane, in newtons?

User Dyachenko
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1 Answer

6 votes

Answer:

3.014 x 10⁻⁸ N

Step-by-step explanation:

q = magnitude of charge on the supersonic jet = 0.55 μC = 0.55 x 10⁻⁶ C

v = speed of the jet = 685 m/s

B = magnitude of magnetic field in the region = 8 x 10⁻⁵ T

θ = angle between the magnetic field and direction of motion = 90

magnitude of the magnetic force is given as

F = q v B Sinθ

F = (0.55 x 10⁻⁶) (685) (8 x 10⁻⁵) Sin90

F = 3.014 x 10⁻⁸ N

User Atara
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