Question

A piping system is operating at 400 gpm and 28 psi. If the system pressure were increased to 30 psi, what would the resultant flow rate be? ) 426 gpm 392 gpm 414 gpm 433 gpm

Answer 1

428.5 gmp

Step-by-step explanation:

Given that,

A piping system is operating at quantity = 400 gpm

Pressure = 28 psi

Increased pressure = 30 psi

We need to calculate the resultant flow rate

We know that,

The flow rate is directly proportional to pressure

`Q\propto P`

Therefore,

`(Q_1)/(Q_2)=(P_1)/(P_2)`

where,

`Q_1\rightarrow 400\text{ gpm}`

`Q_2\rightarrow x\text{ gpm}`

`P_1\rightarrow 28\text{ psi}`

`P_2\rightarrow 30\text{ psi}`

By substituting into formula

`(400)/(x)=(28)/(30)`

`x=(12000)/(28)\approx 428.5\text{ gpm}`

Hence, The resultant flow rate will be 428.5 gmp

Answer 2

No answer is correct.

Step-by-step explanation:

given data:

Q1 = 400 gpm

P1 = 28 psi

Q2 = ?

P2 = 30 psi

Change in pressure in a pipe is given as

`\Delta P = (32\mu vl)/(D^(2))`

where v is velocity and it is given as
`v = (Q)/(A)`

`\Delta P = (32\mu Ql)/(AD^(2))`

Therefore, change in pressure is directly proportional to flow

thus we have

`(P_(1))/(Q_(1))=(P_(2))/(Q_(2))`

`Q_(2)=(P_(2))/(P_(1))*Q_(1)`

`Q_(2)=(30)/(28)*400 = 428.57 gpm`

`Q_(2) =428.57 gpm`

no answer is correct