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Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = x3 − x2 − 12x + 7, [0, 4]

User Vtortola
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Rolle's theorem works for a function
f(x) over an interval
[a,b] if:


  1. f(x) is continuous on
    [a,b]

  2. f(x) is differentiable on
    (a,b)

  3. f(a)=f(b)

This is our case:
f(x) is a polynomial, so it is continuous and differentiable everywhere, and thus in particular it is continuous and differentiable over [0,4].

Also, we have


f(0)=7=f(4)

So, we're guaranteed that there exists at least one point
c\in(a,b) such that
f'(c)=0.

Let's compute the derivative:


f'(x)=3x^2-2x-12

And we have


f'(x)=0 \iff x= (1\pm√(37))/(3)

In particular, we have


(1+√(37))/(3)\approx 2.36

so this is the point that satisfies Rolle's theorem.

User Mahdi Zarei
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