Question

In the pendulum formula, we use g=9.8 m/s^2 for the acceleration due to gravity on Earth. But what about on Venus? If an astronaut on the surface of Venus swings a 1-meter long pendulum, and it has a period of 2.11 seconds, what is the acceleration due to gravity, g, on Venus?

Answer 1

Option A is the correct answer.

Explanation:

Period of simple pendulum is given by the expression,

`T=2\pi \sqrt{(l)/(g)}`

Where l is the length of pendulum, g is acceleration due to gravity.

Here given for Venus

Period, T = 2.11 s

Length of pendulum, l = 1 m

We need to find acceleration due to gravity, g

Substituting

`2.11=2\pi \sqrt{(1)/(g)}\\\\√(g)=(2\pi)/(2.11)\\\\g=8.87m/s^2`

Acceleration due to gravity of Venus = 8.9 m/s²

Option A is the correct answer.