Question

Let f(x) = x^2-6 and g(x) =10x . Find (g ° f)(x)

Answer 1

10x^2-60

Explanation:

(G o F)(x) is the same as g(f(x)). We know that f(x)=x^2-6. So now you have to find g(x^2-6). To solve for that plug in x^2-6 in for x in the original equation for g(x). You get 10(x^2-6) or 10x^2-60

Answer 2

`(g \circ f)(x)=10x^2-60`

Answer:
`10x^2-60`

Explanation:

`(g \circ f)(x)=g(f(x))`

Replace
`f(x)` with
`x^2-6`.

This gives us:

`(g \circ f)(x)=g(f(x))`

`(g \circ f)(x)=g(x^2-6)`

This means to replace the old input variable with new input,
`(x^2-6)`.

Let's do that:

`(g \circ f)(x)=10(x^2-6)`

They probably want you to distribute:

`(g \circ f)(x)=10x^2-60`