Question

Divide

(3x^2 + 9x + 7) divide by (x+2)

Answer 1

`3x+3+(1)/(x+2)`

Explanation:

We are to divide the polynomial
`3x^2 + 9x + 7` by
`x+2`.

For that, we will first divide the leading coefficient of the numerator
`(3x^2)/(x)` by the divisor.

So we get the quotient:
`3x` and will multiply the divisor
`x+2` by
`3x` to get
`3x^2+6x`.

Next, we will subtract
`3x^2+6x` from
`3x^2 + 9x + 7` to get the remainder
`3x+7`.

Therefore, we get
`3x+(3x+7)/(x+2)`.

Now again, dividing the leading coefficient of the numerator by the divisor
`(3x)/(x)` to get quotient
`3`.

Then we will multiply
`x+2` by
`3` to get
`3x+6`.

Then, we will subtract
`3x+6` from
`3x+7` to get the new remainder
`1`.

Therefore,
`(3x^2 + 9x + 7)/(x+2)=3x+3+(1)/(x+2)`

Answer 2

The remainder is: 3x+3

The quotient is: 1

Explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.