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Divide

(3x^2 + 9x + 7) divide by (x+2)

User Dgw
by
8.1k points

2 Answers

5 votes

Answer:


3x+3+(1)/(x+2)

Explanation:

We are to divide the polynomial
3x^2 + 9x + 7 by
x+2.

For that, we will first divide the leading coefficient of the numerator
(3x^2)/(x) by the divisor.

So we get the quotient:
3x and will multiply the divisor
x+2 by
3x to get
3x^2+6x.

Next, we will subtract
3x^2+6x from
3x^2 + 9x + 7 to get the remainder
3x+7.

Therefore, we get
3x+(3x+7)/(x+2).

Now again, dividing the leading coefficient of the numerator by the divisor
(3x)/(x) to get quotient
3.

Then we will multiply
x+2 by
3 to get
3x+6.

Then, we will subtract
3x+6 from
3x+7 to get the new remainder
1.

Therefore,
(3x^2 + 9x + 7)/(x+2)=3x+3+(1)/(x+2)

User RiZKiT
by
8.2k points
5 votes

Answer:

The remainder is: 3x+3

The quotient is: 1

Explanation:

We need to divide

(3x^2 + 9x + 7) by (x+2)

The remainder is: 3x+3

The quotient is: 1

The solution is attached in the figure below.

Divide (3x^2 + 9x + 7) divide by (x+2)-example-1
User BoSkiv
by
8.2k points

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