Question

M1Q13.) Find the relative frequency of the 2nd class to the nearest tenth of a percent.

Answer 1

Add everything in the frequency column.

= 33

Take class two (3).

Solution:

3/33 * 100%

1/11 * 100%

100/11%

9.1%

Best of Luck!

Answer 2

9.1%

Explanation:

The total number of observations is 33. The number in the second class is 3, so the relative frequency is ...

3/33 × 100% = (100/11)% ≈ 9.1%