Question

How many grams of NaCL are required to prepare 50ml of a 2.0 molar solution​

Answer 1

5.85 gm.

Step-by-step explanation:

We know that,

Normality = Molarity × Molecular weight

Equivalent weight

Since molecular weight of NaCl= equivalent weight = 23+35.5 =58.5

Normality of NaCl= molarity=2

Now,

Normality= weight in gram ×1000

Volume ×equivalent weight

Weight in gram is given by,

=Normality × Volume × equivalent weight

1000

= 2× 50 × 58.5

1000

=5.85 gm.