Answer:
95% of students are between 14 and 18 years old
Explanation:
First we calculate the Z-scores
We know the mean and the standard deviation.
The mean is:
![\mu=16](https://img.qammunity.org/2020/formulas/mathematics/high-school/btjm4idq23yu0u76bbce5i58im9yr0dusx.png)
The standard deviation is:
![\sigma=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/var8kkotrku554f8axg5un6btw36zpu081.png)
The z-score formula is:
![Z = (x-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/high-school/xwgthqxa6srex801qx72k5sn8j5x8u41nr.png)
For x=14 the Z-score is:
![Z_(14)=(14-16)/(1)=-2](https://img.qammunity.org/2020/formulas/mathematics/high-school/fqerxho95pad01yxvh9f6ij32qikypdb4s.png)
For x=18 the Z-score is:
![Z_(18)=(18-16)/(1)=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/q3n00kl6oig270qgdalb0my1q6ear51x7y.png)
Then we look for the percentage of the data that is between
deviations from the mean.
According to the empirical rule 95% of the data is less than 2 standard deviations of the mean. This means that 95% of students are between 14 and 18 years old