Question

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 4.1 m/s, and 65-kg person feels a 455-N force pressing against his back. What is the radius of a chamber?

Answer 1

`r=2.4m`

Step-by-step explanation:

We have to use the centripetal force equation

`Fc=(mv^(2) )/(r)`

we need the radious so we have to isolate "r" and we get

`r=(mv^(2) )/(Fc)`

replacing m=65 kg, v= 4.1 m/s and Fc=455N we get

`r=(65*4.1^(2) )/(455)`

`r=2.4m`

The radius of the amusement park chamber is 2.4m