Question

A heat engine operates between a hot reservoir at 2000°C and the atmosphere (cold reservoir) at 25°C. it produces 50 MW of power while rejecting 40 MW of waste heat. Determine the maximum possible thermal efficiency of the engine in percent.

Answer 1

55.56%

Step-by-step explanation:

Given data

Temprature of hot reservior =2000°c=2273k

Temprature of Cold reservior=25°c=298k

Power produced by engine=50MW

Heat rejected =40MW

we know that Effeciency(η) of heat engine=
`(Work produced)/(heat supplied)`

Also we know that

heat supplied
`\left ({Q_s} \right )=work produced{W}+Heat rejected{Q_r}`

Q_s=50+40=90MW

η=
`(W)/(Q_s)`

η=
`(50)/(90)`

η=55.55%