Question

A process has a AH of +22 kJ and a AS of -13 J/K. At which temperatures is the process spontaneous?

Answer 1

At 1692.31 K.

Step-by-step explanation:

The Gibbs free energy is a measurement of the energy available for the system to realize a change. And can be calculated by the relation of enthalpy, temperature and entropy by the Gibbs equation:

`\Delta G =  \Delta H + T\Delta S`

A procces will be spontaneous if the Gibbs free energy of the system is negative.

So, if we set the ΔG of the system as -.1 J to make it so that the proccess will be spontanteous and input the given values of entropy and enthalpy into the Gibbs equation, we get:

`-.01 J = 22,000 J - T(-13 J/K)`

`T = 1692.3 K`