Question

If f(x)=x/2-3 and g(x)=3x2+x-6, find (f+g)(x)

Answer 1

Explanation:

Answer 2

`(f+g)(x) = 3x^2+(3x)/(2)-9\\or\\(f+g)(x) = (6x^2+3x-18)/(2)`

Explanation:

We are given:

`f(x)=(x)/(2)-3 \,\, and\,\, g(x) = 3x^2+x-6`

We need to find
`(f+g)(x)`

(f+g)(x) can be found by adding f(x) and g(x)

(f+g)(x) = f(x) + g(x)

`(f+g)(x) = (x)/(2)-3+(3x^2+x-6) \\(f+g)(x) = (x)/(2)-3+3x^2+x-6\\(f+g)(x) = 3x^2+(x)/(2)+x-3-6\\(f+g)(x) = 3x^2+(3x)/(2)-9\\(f+g)(x) = (6x^2+3x-18)/(2)`

so, (f+g)(x) is:

`(f+g)(x) = 3x^2+(3x)/(2)-9\\or\\(f+g)(x) = (6x^2+3x-18)/(2)`